This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1847 Excerpt: ...A SLUICE. Rule.--Multiply the square root of the height by eight for the natural, and by Jive for the effective velocity, and the product will be the velocities required. Example--What are the natural and effective velocities for 9 feet head of water? V 9 = 3 X 8 = 24 the natural velocity 9 = 3 x 5 = 15 the effective ...
Read More
This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1847 Excerpt: ...A SLUICE. Rule.--Multiply the square root of the height by eight for the natural, and by Jive for the effective velocity, and the product will be the velocities required. Example--What are the natural and effective velocities for 9 feet head of water? V 9 = 3 X 8 = 24 the natural velocity 9 = 3 x 5 = 15 the effective velocity per second, as may be seen by inspection of the table for finding the discharge through sluices. To find the Head of water that will produce a given natural velocity--Rule Divide the given velocity by 8 and the square of the quotient will be the Head of water required; and in general terms will run thus: --Example.--"What must be the Head of water to produce a natural velocity of 24 feet per second?--= 3 & 32 = 9 o the Head or depth of water required. APPLICATION OF TABLE NO. 8 OF SLUICES. Look for the given head of water in the margin, and under head of discharge per minute, will be found the number of cubic feet discharged per minute due to this head of water, and one square foot of sectional area, which multiplied by the given sectional area of the sluice and the product will be the discharge per minute in cubic feet. Example What would be the discharge per minute from a Sluice 4 feet wide and 15 inches deep having a head of 10 feet of water? The head of water is generally calculated as the height from the centre of the orifice to the surface of the water. The Tabular number opposite 10 feet head of water is 948.66 which multiplied by the sectional area = 4 x 1.3 = 5 gives the discharge per minute in cubic feet =2 4743.3 What will be the discharge per minnte through a circular orifice, one foot diameter, with 9 feet head of water? The velocity of 9 feet head of water is, per table--15 feet per second, or 900 per minute multi...
Read Less
Add this copy of The Principles and Practice of Hydraulic Engineering to cart. $16.27, new condition, Sold by Ingram Customer Returns Center rated 5.0 out of 5 stars, ships from NV, USA, published 2022 by Legare Street Press.
Add this copy of The Principles and Practice of Hydraulic Engineering to cart. $27.44, new condition, Sold by Ingram Customer Returns Center rated 5.0 out of 5 stars, ships from NV, USA, published 2022 by Legare Street Press.
Add this copy of The Principles and Practice of Hydraulic Engineering to cart. $40.83, new condition, Sold by Revaluation Books rated 4.0 out of 5 stars, ships from Exeter, DEVON, UNITED KINGDOM, published 2008 by BiblioBazaar.
Add this copy of The Principles and Practice of Hydraulic Engineering to cart. $42.88, new condition, Sold by Revaluation Books rated 4.0 out of 5 stars, ships from Exeter, DEVON, UNITED KINGDOM, published 2008 by BiblioBazaar.
