This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1896 Excerpt: ...resistance in circuit the same when testing from either end. Then, by using testing batteries of approximately the same E.M.F. and resistance, and similar bridge ratios, the current through the fault is the same, and its resistance constant for the time being. The resistance to add is soon found by working out one or ...
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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1896 Excerpt: ...resistance in circuit the same when testing from either end. Then, by using testing batteries of approximately the same E.M.F. and resistance, and similar bridge ratios, the current through the fault is the same, and its resistance constant for the time being. The resistance to add is soon found by working out one or two pairs from both ends, each end freeing in turn. The following is the procedure. Take a pair of readings with zinc and copper, the other end being free, and work out result by formula. Free while the other end tests. The difference of the two results in ohms is then added to the end of cable nearest fault. Take readings from each end again as above. Call result A that obtained at end nearest to fault (after subtracting resistance added to this end), and result P that obtained at the other end. Then distance of fault in ohms from nearest end of cable is L + A-Pohms, 2 where L is the normal copper resistance of the whole cable.-When it is possible to test from both ends in the above manner the results are very reliable if taken fairly rapidly in succession. A wider range in varying the testing current can be attained by the use of different resistances in the battery circuit instead of different bridge ratios, with the additional advantage that the sensitiveness of the galvanometer remains constant. A pair of readings is taken as follows: --With equal ratio a/a and total resistance b in battery circuit, balance obtained is A ohms. With same ratio and total resistance &1 in battery circuit, balance obtained is B ohms. (Resistances b and 6i both include the resistance of battery and whatever extra resistance is added to vary the current.) If Bexceeds A as before (by having bx greater than 6) we have--Resistance of cable up to fault, -! _ A (2 .
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Add this copy of Submarine Cable Laying And Repairing to cart. $22.29, new condition, Sold by Ingram Customer Returns Center rated 5.0 out of 5 stars, ships from NV, USA, published 2022 by Legare Street Press.
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New. Trade paperback (US). Glued binding. 428 p. In Stock. 100% Money Back Guarantee. Brand New, Perfect Condition, allow 4-14 business days for standard shipping. To Alaska, Hawaii, U.S. protectorate, P.O. box, and APO/FPO addresses allow 4-28 business days for Standard shipping. No expedited shipping. All orders placed with expedited shipping will be cancelled. Over 3, 000, 000 happy customers.
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Add this copy of Submarine Cable Laying And Repairing to cart. $33.45, new condition, Sold by Ingram Customer Returns Center rated 5.0 out of 5 stars, ships from NV, USA, published 2022 by Legare Street Press.